evaluate limit x tends to zero x (e^x-1)/1-cos 2x Share with your friends Share 3 Varun.Rawat answered this limx→0 x ex-11 - cos 2x=limx→0xex-12 sin2x=12limx→0 ex-1x2x. sin2x=12limx→0ex-1xsin2xx2=12×limx→0 ex-1x ÷ limx→0sin xx2=121 ÷ 12 as, limθ→0eθ-1θ = 1; limθ→0 sin θθ = 1=12 -2 View Full Answer
