evaluate tan^-1 [tan (5pi/6) + cos^-1 [cos (13pi/6)] Share with your friends Share 3 Tanveer Sofi answered this We havπetan-1tan5π6+cos-1cos13π6=tan-1tanπ-π6+cos-1cos2π+π6=tan-1-tanπ6+cos-1cosπ6 As, tanπ-θ=-tanθ and cos2π+θ=cosθ =tan-1tan-π6+cos-1cosπ6=-π6+π6 As, tan-1tanθ=θ, for all -π2<θ<π2 and cos-1cosθ=θ, for all 0≤θ≤π=0Therefore,tan-1tan5π6+cos-1cos13π6=0 27 View Full Answer
