Evaluate using sutable identity (a+2b+4c)^2-(a-2b-4c)^2 Share with your friends Share 1 Saksham Tolani answered this Dear Student, =(a+2b+4c)2-(a-2b-4c)2 Since, (x+y+z)2=x2+y2+x2+2(xy+yz+xz)=a2+4b2+16c2+2(2ab+16bc+8ac)-a2+4b2+16c2+2(-2ab+16bc-8ca)=a2-a2+4b2-4b2+16c2-16c2+4ab+4ab+32bc+32bc+16ac-16ac=8ab+64bc=8b(a+8c) Regards! 1 View Full Answer