events A B and C are exhaustive events . the odds against A are 8:3 and in favour of B are 2:5. find the odds in favour of C

Given, three events A,B, and C are exhaustive. So,PA+PB+PC=1     .....1Now,Odds against A are 8:3, so,PA=38+3=311And, Odds against B are 5:2, so,PB=25+2=27Put these values in equation 1,311+27+PC=1PC=3477PC¯=1-PC=1-3477=4377Thus, odds in favour of C are PC:PC=3477:4377=34:43

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