every option with multiple choice want ans of every option and it is a multiple choice match column fats asap tommorrow Share with your friends Share 0 Vartika Jain answered this Dear Student, (A) Total moles of chloride in solution :(0.2 mol/L) (0.100 L)(3 chlorideformula unit)=0.06 mol(0.1 mol/L) (0.400 L) (1 chlorideformula unit)=0.04 mol0.06 mol + 0.04 mol = 0.10 mol of chloride[Cl-]=Number of molesVolume of solution=0.100.100+0.400=0.100.500=0.2 MTotal moles of cations in solution:(0.2 mol/L) (0.100 L)(1 Aluminiumformula unit)=0.02 mol(0.1 mol/L) (0.400 L) (1 Hydrogenformula unit)=0.04 molTotal moles = 0.02+0.04=0.06 molTotal concentration of cation=0.060.500=0.12 MHence, correct answer are (p) and (s)(B) Moles of KCl=0.4 mol/L×0.05 L=0.02 molNow, Volume of solution = 50 ml +50 ml=100 ml=0.1 LMolarity=0.020.1=0.2 M[KCl]=[K+]=[Cl-]=0.2 MHence, correct option is (s)(C) moles of K2SO4=0.03×0.2=0.006 molesVolume of solution= 30 ml+70 ml=100 ml=0.1 LNow, Molarity=0.0060.1=0.06 M[K2SO4]=[SO42-]=0.06 MHence, correct answer is (q)D) 24.5% (w/v) H2SO4 means 24.5 g of H2SO4 is present in 100 ml of solutionMolarity=24.598×1000100=2.5 MSince H2SO4 is a strong acid, therefore it dissociates completelyHence, [H2SO4]=[SO42-]=2.5 MThe correct answer is (r) 0 View Full Answer
every option with multiple choice want ans of every option and it is a multiple choice match column fats asap tommorrow