Expert please advise me how to do this question

Dear student,

The solution to your question 7 has been provided below;

​​​​​​As the triangle is right angled, one of the angles is ${90}^o$.

So, let the two acute angles be $4x,5x$

As, sum of all angles of a triangle=${180}^o$

we have,

$4x+5x+90=180$

$9x+90=180$

$9x=180-90$

$9x=90$
$x=90/9$
$x=10$

Therefore, the angles are-

$4x=4*x=4*10={40}^o$

$5x= 5*x= 5*10= {50}^o$

therefore, the three angles of the triangle are ${40}^o, {50}^o and {90}^o$

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