Expert please help me out with this question.

Dear Student,
Two equal angles of isosceles triangle = ${65}^0$
Sum of angles of a triangle = ${180}^0$
$$\begin{gathered} \angle 1+\angle 2+\angle 3= 180° \\ 65°+65°+\angle 3= 180° \end{gathered}$$ 

Two equal angles measure ${65}^0$
${130}^0+\angle 3=180°$
$\angle 3= 180°-130°= 50°$
Angles of an isosceles triangle: 
$65°, 65°, 50°$. ANSWER 

Regards