Experts please find
Angle CDB and,
Angle ADB

Dear student,
Assuming the given figure is a parallelogram ABCDsince ABCDADB=CBD  --[alt int. angles]ADB=80°In ADBA+ADB+ABD=180°70°+80°+ABD=180°ABD=180°-150°ABD=30°Now, ABD=CDB --[alt int. s]CDB=30°
Regards

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