Experts please help in 8th 8 The equation of the circle which has normal x-1y-2=0 and a tangent - Maths -

Question

Experts please help in 8th

8 The equation of the circle which has normal x - 1 y - 2 = 0 and a
tangent 3 x + 4 y = 6 is
(1) x 2 + y 2 - 2 x - 4 y + 4 = 0
(2) x 2 + y 2 - 2 x - 4 y + 5 = 0
(3) x 2 + y 2 = 5
(4) x - 3 2 + y - 4 2 = 5

Rajat Goyal · Accepted Answer

Experts please help in 8th 8. The equation of the circle which has normal x - 1 y - 2 = 0 and a tangent 3 x + 4 y = 6 is (1) x 2 + y 2 - 2 x - 4 y + 4 = 0 (2) x 2 + y 2 - 2 x - 4 y + 5 = 0 (3) x 2 + y 2 = 5 (4) x - 3 2 + y - 4 2 = 5

Experts please help in 8th

8. The equation of the circle which has normal $(x - 1) (y - 2) = 0$ and a tangent $3 x + 4 y = 6$ is
(1) $x^{2} + y^{2} - 2 x - 4 y + 4 = 0$
(2) $x^{2} + y^{2} - 2 x - 4 y + 5 = 0$
(3) $x^{2} + y^{2} = 5$
(4) ${(x - 3)}^{2} + {(y - 4)}^{2} = 5$