Experts please help me with q33

Solution:
2M BaClwill show maximum dissociation as Ba2+ and Cland Cl-. So it will have more number of solutes binding to the water molecules, and so lesser number of water molecules will be available in 2M BaCl2. 1M NaCl will also show dissociation into Na+ and Cl-​​​​​​. Here also, comparative to 1M glucose solution, more number of water molecules will be occupied. Since, glucose does not show dissociation, the number of water molecules freely available will be highest in it. So 1M glucose is expected to have a greater kinetic energy in water molecules. 

Please get the concept cross-checked with your chemistry teacher once. 

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Ans (c) 2M BaCl2 is expected to possess greater kinetic energy in water molecules

This is because BaCl2 dissociates into three ions (Ba2+ and 2 Cl-) in solution, resulting in a greater number of solute particles per unit volume compared to 1M NaCl and 1M glucose.
According to the colligative properties of solutions, the boiling point elevation and freezing point depression of a solution depend on the number of solute particles in the solution

Thus,
2M BaCl2 would be expected to have a greater effect on the boiling point elevation and freezing point depression than 1M NaCl or 1M glucose.
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