Experts, pls solve qn 12(a and b) both....I have exam tomorrow...urgent....
(A)
The possible values when we throw the dicw twice are as follows:
(1,1), (1,2), .......(1,5), (1,6)
(2,1), (2,2), .......(2,5), (2,6)
similarliy goes upto
.
.
.
(6,1), (6,2), .......(6,5), (6,6).
on seeing the above table we can see that no of ways in which we can get doublet primes are 9 doublet primes.
so ur ans is 9/36 = 1/4
(B)
similarly from the above table we can see that their are
in first and fifth row -> 2
in second and forth row ->0
in third row -> 4
in sixth row -> 3
so total = 11
final ans = 11/36.
I Hope that ypu got the required ans. THANKS for askin questions.
The possible values when we throw the dicw twice are as follows:
(1,1), (1,2), .......(1,5), (1,6)
(2,1), (2,2), .......(2,5), (2,6)
similarliy goes upto
.
.
.
(6,1), (6,2), .......(6,5), (6,6).
on seeing the above table we can see that no of ways in which we can get doublet primes are 9 doublet primes.
so ur ans is 9/36 = 1/4
(B)
similarly from the above table we can see that their are
in first and fifth row -> 2
in second and forth row ->0
in third row -> 4
in sixth row -> 3
so total = 11
final ans = 11/36.
I Hope that ypu got the required ans. THANKS for askin questions.