Experts plz explain this Q Share with your friends Share 0 Anurag Kumar answered this Dear Student ,Given, Magnetic field, B=700Gθ=30°Torque acting, T=0.014Nm Since Torque acting on magnet is given by :T=MBsinθ∴M= TBsinθ ⇒M=0.014700*10-4*sin30°M=0.4 A-m2This is required magnetic moment. Work done by the external force to move the magnet from stable to unstable position is given by,W=−MB[cosθ2−cosθ1] W=−MB(−1−1)=2MB W=2×0.4×700×10-4 =0.048J Regards 0 View Full Answer