experts this is urgent can you please answer my following Q fast

how AD2= 900+1/4 AD2BECOMES

3/4AD2= 900 IN CHAPTER CIRCLES EXERCICE 10.4 QUESTION6

its very urgent please

  • 0

Question 6:

A circular park of radius 20 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. Find the length of the string of each phone.

Answer:

It is given that AS = SD = DA

Therefore, ΔASD is an equilateral triangle.

OA (radius) = 20 m

Medians of equilateral triangle pass through the circum centre (O) of the equilateral triangle ASD. We also know that medians intersect each other in the ratio 2: 1. As AB is the median of equilateral triangle ASD, we can write

∴ AB = OA + OB = (20 + 10) m = 30 m

In ΔABD,

AD2= AB2+ BD2

AD2= (30)2+

Therefore, the length of the string of each phone will bem.

  • 0

Hey Titanicaly Talented will give you another solution.

First take the ratio of the radius and te other line on the equilateral triangleas 2:1

therefore radius is = 20m and OD is equal to 10m. Now usingeqilateral triangle theorum 202 - 102 = 300

which is 10root3

Now lenghth of string is 10 root 3 x 2 = 20 root3.

Hope this helps you talented person

  • 0
What are you looking for?