Explain how to answer this :

Given that Conc. HNO₃ = 63%
& density of HNO₃ = 1.4 g/ml

Now, Take 1.0 L of this solution having mass = 1,400 g

Mass of HNO₃ in 1.0 L = $\frac{63}{100} x 1400 = 882 g$

Molar mass HNO₃ = 1 + 14 + 3 x 16 = 63 g/mol

moles of  HNO₃ in 882g = $\frac{882 g}{63 g mo{l}^{-1}}$ = 14.0 mol

Molarity of solution = 14.0 M

Calculate volume required to produce 250mL of 1.20M solution by using molarity equation

M₁V₁ = M₂V₂

14.0 M x V1 = 1.20 M x 250 mL

V1 = $\frac{1.20 M x 250 mL}{14.0 M}$

V1 = 21.4 mL

Volume required = 21.4 mL
Hence option (B) is correct

Regards