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 Explain n(AuB) =n(A) +n(B)-n(A intersection B)?

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The relation given you can be explained as,
Using this relation, you can solve various problems.
 

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n(AuB) =n(A)+n(B) minus n(A intersection B)

suppose,A={1,2,3,4}  B={4,5,6,7}

thus,(AuB)={1,2,3,4,5,6,7}   and (A intersection B)={4}

n(A)=4  n(B)=4  n(AuB)=7  n(A intersection  B)=1

therefore,7=4+4-1=7

hence proved that,n(AuB)=n(A)+n(B)-n(A intersection B) 

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EXACTLY WHAT MERIT NATION EXPERT SAID

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