Explain the answer in detail.. Q). When S O 2 is passed through acidified solution of potassium dichromate, then chromium sulphate is formed. The change in valency of chromium is (a) +4 to +2 (b) +5 to +3 (c) +6 to +3 (d) +7 to +2
Dear Student,
Reaction Involved:
K2Cr2O7 + SO2 + 3H2SO4 K2SO4 + Cr2(SO4)3 + 3H2O
The Oxidation state of Chromium in K2Cr2O7 is:
2x + 7(-2) = -2
x = +6
And
The Oxidation State of Chromium in Cr2(SO4)3 is:
2x + 3(-2) =0
x = +3
So, Oxidation state of Chromium changes from +6 to +3.
Therefore, option (c) is correct.
Hope this information clears your doubts about the topic.
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Reaction Involved:
K2Cr2O7 + SO2 + 3H2SO4 K2SO4 + Cr2(SO4)3 + 3H2O
The Oxidation state of Chromium in K2Cr2O7 is:
2x + 7(-2) = -2
x = +6
And
The Oxidation State of Chromium in Cr2(SO4)3 is:
2x + 3(-2) =0
x = +3
So, Oxidation state of Chromium changes from +6 to +3.
Therefore, option (c) is correct.
Hope this information clears your doubts about the topic.
Keep asking!!
Regards