Explain the formation of fringes due to a single slit, when path difference of light waves from the ends of the slit on reaching a point is (i)lambda (ii)3/2 lambda.

-Wave Optics

Solution
Diffraction through single slit is well explained in our studymaterial. Link is given below
https://www.meritnation.com/cbse-class-12-science/physics/physics-part-ii/wave-optics/studymaterial/46_4_216_254_8671
Formation of fringes 
When path difference is λ 
We get general condition of minima
asinθ=nλ   ...(ii)


The position of nth maxima will be given by
asinθ=(n+1/2​)λ
n =1
asinθ=(3/2​)λ

So when path difference is (3/2​)λ we get secondary maxima.

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