Dear student y=xx=-x2 from x=-1 to x=0and y=xx=-x2 from x=0 to x=1Area between x=-1 to x=0 is∫-10-x2dx +∫01x2dxA1=∫-10-x2dx =x33x=0x=-1 (area cannot be negative so mode is taken)A1=13A2=∫01x2dx=x33x=1x=0=13Total area is =13+13=23square unitRegards

Explain the graph

Dear student

y = x |x| = - x^{2} f r o m x = - 1 t o x = 0 a n d y = x |x| = - x^{2} f r o m x = 0 t o x = 1 A r e a b e t w e e n x = - 1 t o x = 0 i s \int_{- 1}^{0} - x^{2} d x + \int_{0}^{1} x^{2} d x A_{1} = |\int_{- 1}^{0} - x^{2} d x| = {|\frac{x^{3}}{3}|}^{x = 0}_{x = - 1} (a r e a c a n n o t b e n e g a t i v e s o m o d e i s t a k e n) A_{1} = \frac{1}{3} A_{2} = \int_{0}^{1} x^{2} d x = {|\frac{x^{3}}{3}|}^{x = 1}_{x = 0} = \frac{1}{3} T o t a l a r e a i s = \frac{1}{3} + \frac{1}{3} = \frac{2}{3} s q u a r e u n i t R e g a r d s

View Full Answer