explain the integration part of the following equation

Dear Student,

iavg=i00Tsinωt dt0Tdtintegration of sinωt=-cosωtωiavg=i0-cosωtω0Tt0Tiavg=i0ω-cosωT--cos0°T-0iavg=i0-cos2πTT--1ωT  ..............  ω=2πTiavg=i0-cos2π+1ωTiavg=i0-1+1ωT  .......... cos2π=1iavg=i0×0ωTiavg=0
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