Explain this given problem :

Dear Student,

The reaction is as follows:
4A  +  2B    +  3C   →  A4B2C3

4 moles of A react with 2 moles of B
2 mole of A will react with 2 / 2 mole of B
= 1 moles of B
We have 1.2 moles of B.
4 moles of A react with 3 moles of C
2 mole of A will react with 3 / 2 mole of C
= 1.5 moles of C
But we have only 1.44 moles of C. So limiting reagent is C in this reaction.
3 moles of C react to form 1 mole of A4B2C3

1.44 moles of C will form = 1 third cross times 1.44
= 0.48 moles of A4B2C3​. 
Hence correct option is (c).

Regards

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