Explain this question. Q. A uniform chain of mass M and length L is kept on a table. Suppose L n length hangs down the table, what work has to be done by the applied force and gravity in order to pull the chain up the table. Share with your friends Share 0 Chandra Prakash answered this dear student consider a element dm of length dx at a distance below the table here dm= ml*dxsmall amount of work done to ull it a height x is dw=dmgxwhich is dw=mldx*g*xtotal work done = ∫dw=∫0L/nmgxdxl=mgx220L/nl =mgln2 AS Work done by gravity is negative of work done by external force so work done by gravity = -mgln2 answer 0 View Full Answer