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Q. A uniform chain of mass M and length L is kept on a table. Suppose  L n  length hangs down the table, what work has to be done by the applied force and gravity in order to pull the chain up the table.


dear student consider a element dm of length dx at a distance below the table here dm= ml*dxsmall amount of work done to ull it a height x is dw=dmgxwhich is dw=mldx*g*xtotal work done = dw=0L/nmgxdxl=mgx220L/nl =mgln2 AS Work done by gravity is negative of work done by external force so work done by gravity = -mgln2 answer 

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