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Dear student,
The correct answer is option (3).i.e. H2SO3
H2SO3 will have 2:1 ratio of normality to molarity as the n factor in this case is 2 and we know that
So if molarity is 1M and n factor is 2 then normality will be 2N and hence the ratio of normality to molarity is 2:1.
n factor is number of equivalents of H+ or OH-.
In case of Al(OH)3 the n factor is 3 Therefore here the ratio of normality to molarity is 3:1.
In case of KOH and HCl the n factor is 1 so the ratio of normality to molarity is 1:1.
Regards
The correct answer is option (3).i.e. H2SO3
H2SO3 will have 2:1 ratio of normality to molarity as the n factor in this case is 2 and we know that
So if molarity is 1M and n factor is 2 then normality will be 2N and hence the ratio of normality to molarity is 2:1.
n factor is number of equivalents of H+ or OH-.
In case of Al(OH)3 the n factor is 3 Therefore here the ratio of normality to molarity is 3:1.
In case of KOH and HCl the n factor is 1 so the ratio of normality to molarity is 1:1.
Regards