Explain why a ray of light passing through the centre of curvature of a concave mirror is reflected along same path? Should I explain this mathematically? Since it's perpendicular as radius is always perepndi,. So angle of incidence = angle of ref ... ?? Share with your friends Share 0 Decoder_2 answered this Dear student,As law of reflection states that angle of reflection is always equal to the angle of incidence.These two angle are taken with respect to the normal or perpendicular drawn to the mirror.In case of concave mirror the normal is the line drawn across the centre of curvature pointSo if a ray falls on it the angle of incidence will be 0degree and hence to obey law of reflection angel of reflection must be 0degree.Hence light is reflected bath in the same path.Regards 1 View Full Answer Shraiyanah answered this When a ray of light passes through the centre of curvature it makes an angle of 0 degree. It means that angle I is always equal to angle r. And in a concave mirror ray of light passes through the Centre of curvature then the incident ray makes an angle of 0 degree with centre of curvature so angle of r will also be 0 degree so it retraces the path. Yes..proving it mathematically would be a better option. Hope this would help you 0
