Express in form of a+ib

(1-i)/(1+i)...

Please help me expert......

(1-i)/(1+i)

= (1-i)*(1-i)/(1+i)*(1-i) {Rationalising the denominator}

= (1-i)2/(12-i2)

= (1+i2-2i)/(12-[-1])

= (1-1-2i)/(2)

= (-2i)/2

= -i

= 0+(-1)i   {In the form a+ib where a=0 and b=-1}

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(1-i)/(1+i)

=(1-i)*(1-i)/(1+i)*(1-i)

=(1-i)2/ (1)2 - (i)2

=1+i2-2i /1-i2

=-2i / 2 = -i

so, a+ib = 0-i

so, a = 0    b=-1

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Express the product (1+i) (1+2i) in a+ib form
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