express ( -root3+root-2) (2 root 3-i) in the form of a + ib please show all the steps teacher.. Share with your friends Share 2 Mayank Jha answered this Dear student, We can use the following method to solve this question. -3+-223-i=-3+2i23-i=-6+3i + 26i + 2=2-6+i3 + 26The above expression is in the form of a+ib, wherea = 2-6 and b = 3 + 26 Regards 5 View Full Answer Saksham answered this rthmnthmr 0 Ravi Else answered this (-√3+√-2)(2√3-i) √-2=√2i (-√3+√2i)(2√3-i) Now multiply -6 +√3i+2√6i-√2 now separate real & imaginary part (-6-√2) + (2√6+√3)i 2
