EXPRESS WORK DONE IN AN ELECTRIC FIELD IN TERMS OF CHARGE AND POTENTIAL DIFFERNCE ? CALCULATE THE AMOUNT OF WORK DONE IN CARRYING A CHARGE OF 5mC AGAINST A POTENTIAL DIFFERENCE OF 100 V??

The work done in an electric field in terms of charge (q) and potential difference (V) is given by,
 W=qV

The work done,
W=qVW=5×10-3×100=0.5 J
The work done in this case is 0.5 J.

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