F = 2xy i + x2 j
Body is taken from (-1,2) to (1,3)

Find the work done

Dear student 
try to convert force relation into exact differential form only then you can calculate work done 
dw =F.dr =F.(dxi+dy)(2xyi+x2yj)(dxi+dy) =(2xydx) +x2ydy  =d(x2y) =x2y-1,21,3 =1-1 =0 now initial at -1,3  x2y = (-1)23 =3at (1,3)    x2y=3 

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