f(x) = x2 - 3x + 1, find k if
f(2k) = 2f(k) and f(2k) = f(k)
Hi Narayana!
Here is the answer to your question.
f(x) = x2 – 3x + 1
f(2k) = 2f(k)
∴ (2k)2 – 3(2k) + 1 = 2 (k2 – 3k + 1)
⇒ 4k2 – 6k + 1 = 2k2 – 6k + 2
⇒ 2k2 – 1 = 0
f(2k) = f(k)
∴ (2k)2 – 3(2k) + 1 = k2 – 3k + 1
⇒ 4k2 – 6k + 1 = k2 – 3k + 1
⇒ 3k2 – 3k = 0
⇒ 3k (k – 1) = 0
⇒ k = 0 or k – 1 = 0
⇒ k = 0 or k = 1
The value of k is 0 or 1.
Cheers!