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factorize 8p³+12/5p²+6/25p+1/125

8 p^{3} + \frac{12}{5} p^{2} + \frac{6}{25} p + \frac{1}{125} = 8 p^{3} + \frac{1}{125} + \frac{12}{5} p^{2} + \frac{6}{25} p = {(2 p)}^{3} + {(\frac{1}{5})}^{3} + 3 {(2 p)}^{2} (\frac{1}{5}) + 3 (2 p) {(\frac{1}{5})}^{2} = {(2 p + \frac{1}{5})}^{3} [a s, a^{3} + b^{3} + 3 a^{2} b + 3 a b^{2} = {(a + b)}^{3}] = (2 p + \frac{1}{5}) (2 p + \frac{1}{5}) (2 p + \frac{1}{5})

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