factorize x2+3x-28,hence find x such that 4x+3.2x-28=0

Dear Student,

Please find the attached solution.

1) Factorize x2+3x-28x2+3x-28 =x2-4x+7x-28=x(x-4)+7(x-4) =(x-4)(x+7)2) 4x+3.2x-28 = 0t2+3t-28 = 0             [ put 2x = t ] t2-4t+7t-28 = 0 t(t-4)+7(t-4) = 0(t-4)(t+7) = 0t = 4 of t = -7 2x = 4 or  2x = -7 2x = 22  or 2x = -7x = 2  or  2x = -7

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