Fidn the area of a rhombus one side of which measures 20 cm and one of whose diagonals is 24 cm.
Let We Join The Diagonals
Diagonals Of A Rhombus Bisect Each Other At Right Angles
1/2*24 = 12 cm (As They Bisect Each Other)
Now Side Acts As Hypoteneuse
Diagonal^2 = 20^2-12^2
Diagonal^2 = 256 cm
Diagonal = 16 cm
Area = 1/2*24*16 = 192 cm^2