find a,b,c if f(x)= (sin(a+1)x+sinx)/x ,x<0

c ,x=0

(under root x+bx)-(under root x)/b under root x3, x>0 is constant at x=0

f0-0=limh0sina+10-h+sin0-h-h=limh0sina+1h+sinhh=a+1h+hh=a+2  limh0sinh=hand f0+0=limh0h+bh2-hbh32=limh01+bh12-1bh=limh01+12bh+........-1bh=12which is independent of b so b may have any real value.Again by continuity at x = 0 , we have a+2=12=cSo a = -3/2 and c = 1/2.

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