find a quadratic polynomial whose sum and product are -8 and 12 respectively hence find the zereos Share with your friends Share 0 Manbar Singh answered this We have,sum of zeroes = S = -8Product of zeroes = P = 12Now, required polynomial is px = kx2-Sx+P, where k is a non zero real number=kx2 + 8x+12=x2 + 8x+12 On taking k = 1Now, zeroes of px are given by solving the equation px = 0⇒x2 + 8x+12 = 0⇒x2 + 6x + 2x + 12 = 0⇒xx + 6 + 2x + 6 = 0⇒x+2x+6 = 0⇒x + 2 =0 and x+6 = 0⇒x = -2 and x = -6 0 View Full Answer Gopika answered this Alpha + beta = -8 Alpha × beta =12 General form of quadratic polynomial - =x2- (alpha + beta )x + (alpha × beta ) =x2- (-8) x + (12) =x2+8x +12 Therefore, the required quadratic polynomial is x2 + 8x + 12 0 Clifton D Silva answered this SUM:= -8 PRODUCT= 12 THEREFORE THE QUADRATIC POLYNOMIAL IS x2+8x+12 NOW FACTORISE THE POLYNOMIAL TO OBTAIN ITS ZEROES. x2+8x+12 x2+2x+6x+12 x(x+2)+6(x+2) (x+6)(x+2) now equate both with zero x+6=0 x+2=0 x= -6 x= -2 THEREFORE THE ZEROES ARE -6 AND -2 -1
