Find approximately the distance at which a globe,5 1/2 cm in diameter will subtend an angle of 6'

Dear student

We have,θ=6'=660°=110×π180c=π1800 radianNow, sinθ=BCACsinπ1800=2.75ACAC=2.75sinπ1800=2.750.00175   as sinπ1800 =0.00175...  (approx) =1571.42 cm
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