find: base = 20 cm , area of parallelogram= 246cm sq , find = height =

height = 15cm , area of parallelogram= 154.5 cm sq. find base .

height= 31.4cm , area of triangle= 1256mm . find base of triangle.

answer it fast , and answer the que step by step .please.

1) Base; b = 20 cm
suppose the height of parallelogram be h cm.
So, area of parallelogram = b×h = 20×h = 246 cm2
20h = 246h = 24620 = 12.3
So height of parallelogram is 12.3 cm.

2) Suppose the base of parallelogram is b cm.
Height of parallelogram; h = 15 cm
So, area of parallelogram = b×h = b×15 = 154.5 cm2
15b = 154.5b = 154.515 = 10.3
So base of parallelogram is 10.30 cm.

3) Suppose base of triangle is b mm.
Height; h = 31.4 cm = 314 mm
So area of triangle = 12×b×h = 12×b×314 = 1256 mm2
b = 1256×2314 = 8
So base of triangle is 8 mm.

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1. Area of the parallelogram = base * height

246cm = 20 cm * h

246cm / 20cm = height

height = 12.3 cm

2. A= h* b

154.5cm = 15cm * b

154.5cm /15cm = b

Base = 10.3 cm

3. A= h * b

1256 mm = 125.6 cm

125. 6 cm = 31.4cm * b

125.6cm /31.4cm = b

base = 4 cm

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1.Area of parallelogram=base*hieght

=246 sq.cm =b*h

if b=20cm

h=?

246 cm=20*h

=h=246/20=12.3cm

therefore height =12.3cm

2.A=b*h

154.5cm=b*h

h=15

b=?

A=b*h

154.5=15*b

=154.5/15

=b=10.3cm

3.A=h*b

1256 mm=12.56cm=31.4*b

b=125.6/31.4=4

There fore base =4 cm

A=area of parralellogram

B=Base

H= height

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