find d/dx [sin^-1 (3x/2 - x^3/2)]

fx=sin-13x2-x32Let 3x2-x32=uSo, fx=sin-1uNow, dfdx=dfdu×dudx, by chain rule=11-u232-32x32-1=11-u232-32x12=32-32x121-3x2-x322(substituting 'u' back)

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