Find domain of 10x+10y =10.

10x + 10y = 10

⇒ 10y = 10 – 10x

⇒ 10y = 10 (1 – 10x – 1)

⇒ log10 10y = log10 10 + log10 (1 – 10x – 1)

y = 1 + log10 (1 – 10x – 1)

Now, for y to be defined log10 (1 – 10x – 1) must be defined.

i.e., 1 – 10x – 1 > 0

⇒ 1 > 10x – 1

⇒ 10 > 10x

i.e. 10x < 101

x < 1

∴ Domain: (– ∞, 1)

  • 66

10x + 10y=10

log10(10x)+ log10(10y)=log1010

x+y=1

x=1-y

domain=R

  • -50
What are you looking for?