Find domain of function cos inverse(3x-2).

  • -1<=3x-2<=1
  • 1<=3x<=3
  • 1/3<=x<=1
hence range of the function is[1/3,1]

 

  • 4
(arccos means cos inverse)
Domain of arccos x is [-1,1]
So here -111/3 Therefore x belongs to [1/3 , 1]
  • -7
Since, domain of cos inverse = [-1,1] So, cos^1 (3x-2)=[1/3,1]
  • 1
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