Find domain of the following function given below

Solution 
Assuming your question as "solve the inequality (x² ​​​​​- 3) > 1"
x² - 3 > 1
Adding 3 on both sides, we get,
​​​​​​x² - 3 + 3 > 1 + 3
x² > 4
{For uⁿ > a, if n is even, then u < $-\sqrt[n]{a} or u>\sqrt[n]{a}$}
So, $x<-\sqrt{4} or x>\sqrt{4}$
Therefore, x < - 2 or x > 2
Interval notation will be 
$\left(-\infty ,-2\right)\cup \left(2,\infty \right)$
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