find dy/dx as a function of x (x+y)^2=4
 

Dear student

(x+y)2=4x2+y2+2xy=4differentiating we get2x+2y(dy/dx)+2x(dy/dx)+2y=0(2x+2y)(dy/dx)=-(2x+2y)dydx=-(2x+2y)(2x+2y)=-1so (dy/dx) as function of x isdydx=-1=-1×x0 =f(x)

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