Find dy/dx, when:

x2 + y2 = log( xy)

The answer: y(1 - 2x2 ) / x (2y2 - 1)

x2+y2=logxyDifferentiating on both side w.r.t. x, we get,2x+2ydydx=1xyxdydx+y2x+2ydydx=1ydydx+1x2ydydx-1ydydx=1x-2xdydx2y2-1y=1-2x2xdydx=y1-2x2x2y2-1

  • 11
What are you looking for?