Find dy/dx, when
X = a log t, y = b sin t
The answer: b t cos t/ a

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Find dy/dx, when
X = a log t, y = b sin t
The answer: b t cos t/ a

Priyanka Kedia · Accepted Answer

Given, x=alogtDifferentiating w r t
 t, we get,dxdt=ddta logt⇒dxdt=addtlogt⇒dxdt=a1t⇒dxdt=atAnd,y=b sintDifferentiating w
r t
 t, we get,dydt=ddtb sint⇒dydt=bddtsint⇒dydt=bcost⇒dxdt=b costThus,dydx=dydtdxdt=b costat=bt costa⇒dydx=bt costa

Find dy/dx, whenX = a log t, y = b sin tThe answer: b t cos t/ a

Find dy/dx, when
X = a log t, y = b sin t
The answer: b t cos t/ a