Find dy/dx, whenX = etheta( sin theta + cos theta ) , y = etheta ( sin theta - cos theta )The answer: tan theta Share with your friends Share 0 Manbar Singh answered this We have, x = eθsin θ + cos θ⇒dxdθ = eθ cos θ - sin θ + sin θ + cos θeθ⇒dxdθ = eθcos θ - sin θ + sin θ + cos θ⇒dxdθ = 2 eθ cos θNow, y = eθsin θ - cos θ⇒dydθ = eθ cos θ + sin θ + sin θ - cos θeθ⇒dydθ = eθcos θ + sin θ + sin θ - cos θ⇒dydθ = 2 eθ sin θNow, dydx = dydθ × dθdx⇒dydx = 2 eθ sin θ × 1 2 eθ cos θ⇒dydx = tan θ 4 View Full Answer
