Find dy/dx, y= tan^-1 1-x/1+x - tan ^-1 x+2/1-2x Share with your friends Share 5 Devesh Kumar answered this y=tan-11-x1+x-tan-1x+21-2xput x = tan θ and 2 = tan αNow, y = tan-1tanπ/4-tan θ1+tanπ/4. tan θ-tan-1tan θ + tan α1 - tan α . tan θy = tan-1tanπ4-θ - tan-1tanθ+αy = π4-θ - θ-αy = π4-2θ-αy =π4-2tan-1x - tan-12⇒dydx = 0 -21+x2 - 0 = -21+x2 26 View Full Answer
