find dy/dx xy2 - x2y -5=0

We have,xy2 - x2y - 5 = 0differentiating with respect to x, we getx 2ydydx + y2 - x2dydx + 2xy + 0 = 0⇒2xydydx - x2dydx = 2xy - y2⇒dydx2xy - x2 = 2xy - y2⇒dydx = 2xy - y22xy -x2

find dy/dx

xy² - x²y -5=0

We have, x y^{2} - x^{2} y - 5 = 0 differentiating with respect to x, we get x . 2 y \frac{d y}{d x} + y^{2} - (x^{2} \frac{d y}{d x} + 2 x y) + 0 = 0 \Rightarrow 2 x y \frac{d y}{d x} - x^{2} \frac{d y}{d x} = 2 x y - y^{2} \Rightarrow \frac{d y}{d x} (2 x y - x^{2}) = 2 x y - y^{2} \Rightarrow \frac{d y}{d x} = \frac{2 x y - y^{2}}{2 x y - x^{2}}

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