Find equation of circle tangent to 2x-3y-7 at (2, -1) & passes through(4, 1)
Dear student
Let the centre of the circle be (h,k)
The circle is tangent to 2x-3y-7 at (2, -1)
slope of normal at (2,-1) which passes through centre (h,k) is -3/2 (perpendicular to tangent with slope 2/3)
radius = distance between points (h,k) and (2,-1)
Circle also passes through(4, 1)
Regards
Let the centre of the circle be (h,k)
The circle is tangent to 2x-3y-7 at (2, -1)
slope of normal at (2,-1) which passes through centre (h,k) is -3/2 (perpendicular to tangent with slope 2/3)
radius = distance between points (h,k) and (2,-1)
Circle also passes through(4, 1)
Regards