Find general solution of:Sin^2x*secx + √3tanx = 0

sin2x.sec x + √3tanx=0
=> sinx.tanx + √3tanx=0
=>tan x (sinx +√3)=0
therefore, either tanx=0 or sinx=-√3
but, -1≤sin x≤1
​so, tan x=0
x=nπ
 
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sin2x.sec x + ?3tanx=0
=> sinx.tanx + ?3tanx=0
=>tan x (sinx +?3)=0
therefore, either tanx=0 or sinx=-?3
but, -1?sin x?1
?so, tan x=0
x=n?
?
  • -1
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