Find general solution of:Sin^2x*secx + √3tanx = 0

sin²x.sec x + √3tanx=0
=> sinx.tanx + √3tanx=0
=>tan x (sin x +√3)=0
therefore, either tan x =0 or sin x=-√3
but, -1≤sin x≤1
​so, tan x=0
x=nπ