find general solution of tan theta tan 2 theta=1

We have,    tan θ . tan 2θ = 1tan θ × 2 tan θ1 - tan2θ = 12 tan2θ = 1 - tan2θ3 tan2θ = 1tan2θ = 13tan2θ = tan2π6θ = ±π6

  • 15
X=npi +1ANDX=npi+1/2
  • 10
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