find general solution of tan theta tan 2 theta=1 Share with your friends Share 5 Manbar Singh answered this We have, tan θ . tan 2θ = 1⇒tan θ × 2 tan θ1 - tan2θ = 1⇒2 tan2θ = 1 - tan2θ⇒3 tan2θ = 1⇒tan2θ = 13⇒tan2θ = tan2π6⇒θ = nπ±π6 20 View Full Answer Ritik answered this X=npi +1ANDX=npi+1/2 12