find k if f (x)={x^2-25/x-5,x not equal to 5 k,x=5 } is continuous at x=5

Dear Student,

fx=x2-25x-5 for x not equal to 5fx=k for x=5rearranging x2-25x-5, we getx-5×x+5x-5fx=x+5 for x not eual to 5.For this function to be continous at x=5fx=5+5=10also fx=k at x=5thusk=10
Regards,

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