Find length & breadth of rectangle whose area is 24 cm2 & perimeter is 20cm

Dear Student,

Let L be length and B be breadth of the rectangle
Area = 24 cm2
Perimeter = 20 cm

​​​​​​Area = 24 = L* B

Perimeter = 2(L+B) = 20
L+B = 10
$$\begin{gathered} B=10-L \\ 24=L\times (10-L) \\ 24=10L-L^2 \\ {L}^2-10L+24=0 \\ {L}^2-6L-4L+24=0 \\ L(L-6)-4(L-6)=0 \\ (L-4)(L-6)=0 \\ L=6, 4 \\ Taking L = 6 so B = 4 \\ Taking L = 4 so B = 6 \end{gathered}$$

Regards
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